CHEM · 2.04 · BONDING
NCEA Level 2 · Chemistry · AS 91164
The Shape of
Bonding
Lewis Structures · VSEPR Shapes · Polarity
nceachemistrytutor.com — Level 2 · VSEPR Theory
02 / 10
The roadmap

Three questions tell the whole story.

Act I

Where do the electrons live?

Lewis structures — count valence electrons, draw bonds and lone pairs. The blueprint of every molecule.

Act II

What shape do they build?

VSEPR theory — electron domains form a parent geometry; lone pairs compress it into predictable shapes and angles.

Act III

Is the molecule polar?

Electronegativity + symmetry — bond dipoles may cancel or combine. This decides how a molecule behaves.

The exam logic: draw the Lewis structure → determine the shape → check bond dipoles & symmetry → decide polar or non-polar. Every question is this chain.
01
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Act I · Lewis structures

Drawing Lewis structures — the 5-step method

  • Count total valence electrons. Add one per negative charge, subtract one per positive charge.
  • Place the least electronegative atom central (H is never central). Connect with single bonds.
  • Complete outer octets of the surrounding atoms with lone pairs.
  • Leftover electrons go on the central atom — as lone pairs.
  • If the central atom lacks an octet, make multiple bonds — turn lone pairs into double/triple bonds.
Watch out

Common traps

✕  Forgetting to adjust for charge — NH₄⁺ has 8 valence e⁻ (5 + 4 − 1), not 9.

✕  Hydrogen only needs 2 electrons — never an octet.

✕  Boron & beryllium can be electron-deficient (BF₃ is fine with 6 e⁻).

Exam habit: show lone pairs as dots and bonding pairs as lines — and label your final answer with the total electron count.
02
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Act I · Worked examples

Lewis structures in practice.

H₂O — 8 e⁻ total O H H 2 lone pairs on O
2 bonding pairs · 2 lone pairs
CO₂ — 16 e⁻ total C O O two double bonds C=O
no lone pairs on C
NH₄⁺ — 8 e⁻ total N H H H H +
5 + 4 − 1 = 8 valence e⁻
Notice: the lone pairs and multiple bonds you draw here directly determine the shape on the next slides.
03
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Act II · Shape of molecules

Every shape starts from its parent geometry

VSEPR: the electron domains around the central atom (bonding pairs + lone pairs) repel and spread as far apart as possible. The arrangement they form is the parent (electron) geometry — it sets the starting bond angle. Lone pairs then compress the observed angle below the parent value.

Electron domainsParent geometryParent angle
2Linear180°
3Trigonal planar120°
4Tetrahedral109.5°

Repulsion strength: LP–LP  >  LP–BP  >  BP–BP — lone pairs sit closer to the nucleus and squeeze bonding pairs together.

Same parent · shrinking angle

All three have 4 domains → tetrahedral parent of 109.5°

CH₄ · 4 BP, 0 LP109.5°
NH₃ · 3 BP, 1 LP≈ 107°
H₂O · 2 BP, 2 LP≈ 104.5°

Rule of thumb: each lone pair costs about 2.5° — but in the exam, always explain it as "less than 109.5° because lone pairs repel more strongly".

Parent first, shape second: the electron geometry is tetrahedral in all three — the molecular shape is named only by where the atoms end up sitting.
04
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Act II · Learn these six

Shapes & bond angles — explained from the parent angle

MoleculeParent geometry (ideal angle)Molecular shapeBond angleWhy the angle is what it is
CH₄Tetrahedral · 109.5°Tetrahedral109.5°4 bonding pairs — repulsion is equal, no lone pairs, so it stays at the parent angle
NH₃Tetrahedral · 109.5°Trigonal pyramidal≈ 107°1 lone pair repels the bonding pairs more strongly, compressing 109.5° → ≈107°
H₂OTetrahedral · 109.5°Bent (V-shaped)≈ 104.5°2 lone pairs repel the bonding pairs even more, compressing 109.5° → ≈104.5°
BF₃Trigonal planar · 120°Trigonal planar120°Only 3 bonding pairs, no lone pairs — stays at the parent 120°
CO₂Linear · 180°Linear180°2 double bonds act as 2 domains — stays at the parent 180° (and is symmetric → non-polar)
PCl₅ (ext.)Trig. bipyramidal · 90°/120°Trigonal bipyramidal90° / 120°5 bonding pairs — extension beyond the 4-domain family
Model NCEA answer: "The 4 electron pairs around the central atom form a tetrahedral arrangement based on 109.5°. The lone pair(s) repel more strongly than bonding pairs and are held closer to the central atom, pushing the bonding pairs closer together — so the bond angle is less than 109.5° (≈107° for NH₃, ≈104.5° for H₂O)."
05
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Act III · Polarity part 1

Polar bonds — the tug-of-war for electrons

Atoms share electrons unequally when their electronegativity differs. The more electronegative atom pulls the shared pair closer — creating a dipole.

  • ΔEN < ~0.4 → non-polar covalent bond — electrons shared evenly.
  • ΔEN ≈ 0.4 – 1.7polar covalent bond — partial charges δ⁺ / δ⁻ form.
  • ΔEN > ~1.7 → ionic — electrons effectively transferred.
Example · H–Cl H δ⁺ Cl δ⁻ dipole arrow points to δ⁻ EN: H 2.20 → Cl 3.16 (Δ = 0.96, polar)

The electron cloud shifts toward chlorine. The bond is polar — and a diatomic molecule with a polar bond is always a polar molecule.

Say it properly in the exam: "Cl is more electronegative than H, so the bonding electrons are attracted more strongly to Cl, giving Cl a partial negative charge (δ⁻) and H a partial positive charge (δ⁺)."
06
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Act III · Polarity part 2

Polar vs non-polar molecules.

Polar molecule

Asymmetric — dipoles don't cancel

O H H

Bent shape + polar O–H bonds → the dipole arrows cannot cancel. Polar molecule.

net dipole ≠ 0
vs
Non-polar molecule

Symmetric — dipoles cancel

C O O equal & opposite — point outward to each δ⁻ O, and cancel

Each C=O bond is polar, but the linear symmetry makes the dipoles cancel. Non-polar molecule.

net dipole = 0
Golden rule: polar bonds + symmetric shape → non-polar molecule (CO₂, CH₄, BF₃). Polar bonds + asymmetric shape (lone pairs on the centre) → polar molecule (H₂O, NH₃).
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Putting it together

The 4-step decision chain.

Step 1
Draw the Lewis structure.

Count valence e⁻, place lone pairs, make multiple bonds if needed.
Step 2
Count electron domains.

Bonding pairs + lone pairs around the central atom.
Step 3
Name parent geometry, then shape.

4 domains → tetrahedral parent (109.5°); lone pairs compress the observed angle (≈107°, ≈104.5°).
Step 4
Polar or not?

Polar bonds & asymmetric → polar. Symmetric or even sharing → non-polar.
CH₄ → tetrahedral, 109.5°, non-polar (symmetric)
NH₃ → pyramidal, ≈107° (parent 109.5°), polar
H₂O → bent, ≈104.5° (parent 109.5°), polar
08
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Exam day checklist
Draw it. Shape it.
Decide its polarity.

✓ Lewis structures

Show all lone pairs · label total electrons · H never central

✓ Parent geometry → shape

Tetrahedral parent 109.5°; lone pairs compress to 107° and 104.5° — explain the why

✓ Polar bonds

Electronegativity difference → δ⁺ and δ⁻, dipole arrow points to δ⁻

✓ Polar molecules

Symmetric shapes cancel dipoles (CO₂, CH₄, BF₃) — asymmetry doesn't (H₂O, NH₃)

AS 91164 · nceachemistrytutor.com · Level 2 Chemistry